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回文獎勵 +2 楓幣
本帖最後由 HuangRance 於 2020-5-11 03:10 編輯
yapc1728 發表於 2019-12-3 09:57
【題目】 for the function f(X)=3√x(x-7)²
which of the following statements are true ?
f (0) = 0 ...
【題目】 for the function f(X)=3√x(x-7)²
which of the following statements are true ?
f (0) = 0 is a relative minimum
f (x) is differentiable everywhere
f (7) = 0 is a relative minimum
f (x) has no relative maximum
答案怪怪的
今日題目:
for the function f(X)=3√x(x-7)² which of the following statements are true ?
f (0) = 0 is a relative minimum
f (7) = 0 is a relative minimum
f (x) is differentiable everywhere
f (x) has no relative maximum
【譯文】
對於函數f(X)=3√x(x-7)² 下列哪個陳述是正確的?
f(0)= 0是相對最小值
f(7)= 0是相對最小值
f(x)隨處可微
f(x)沒有相對最大值
====================================================
轉換成javascrit的程式碼如下:
function f(x){return Math.cbrt(x*Math.pow(x-7,2));}
那 f(-3)=3√-3*(-3-7)*(-3-7)= 3√-300=-6.6943295008216952188265932463993
其實簡單驗算可以得知,只要x<0都可以開立方根,有負數解,解可以趨近無限小
同理,只要x>0都可以開立方根,有正數解,解可以趨近無限大
那答案應該比較像f (x) has no relative maximum f(x)沒有相對最大值 ,而我答這個,結果是錯的,然道答案是f (x) is differentiable everywhere f(x)隨處可微,跑程式可得比0小的值,應該不是 f (0) = 0 is a relative minimum f(0)= 0是相對最小值 , f (7) = 0 is a relative minimum f(7)= 0是相對最小值!!!
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